Can someone please help me with this?
-\[-\frac{ 1 }{ 4 }x + \frac{ 1 }{ 10 }y = \frac{ 2 }{ 5 }\]
ok
If you multiply both sides of the equation by the lowest common multiple of those denominators {4, 5, 10}, all those fractions will go away
The question wants me to match the equation to it's graph. Here are the graphs
Isn't the LCM 20?
if you rearrange the equation to the form \[y = mx+b\] you can compare the slope \(m\), and y-intercept \(b\) of the equation with those plots
yeah, multiply both sides of the equation by 20
So (20)-1/4x + (20)1/10y = (20)2/5 hold on im working it on paper
Let x = 0 , solve for y to get the point (0,y) Let y = 0, Solve for x to get the point (x,0) Those are the x and y axis intercepts
Or unkerhaukus way is fine too
Okay I got -5x + 2 = 8 by multiplying it all by 20
i think you mean\[-5x + 2y = 8\] now can you arrange this into \(y=mx+b\) form?
If x=0, y = 20/5 or y=4 so The point x = 0 y=4 is on the line, (0,4) Now let y = 0 and solve for x to get the point (x,0)
ok hold on
If y = 0, you get \[\frac{ -1 }{ 4 }x + 0 = \frac{ 2 }{ 5 }\] solve for x
That is your second point(x-intercept) y=0, x=? (x,0)
The only graphs with a point at (0,4) have 1.5 or -1.5 as the x
yes, which one of those works with the equation when y = 0? (-1/4)x + 0 = 2/5
\[x = \frac{ 2 }{ 5 }*\frac{ -4 }{ 1 }\]
Graph 2 looks like it intersects the x-axis at -8/5 or about - 1.6
Just remember, if you need to choose a graph, the quickest way to do it, is just let x=0 and solve for y, then let y=0 and solve for x. Those 2 points (0 , y) and (x , 0) will define the line for you.
Join our real-time social learning platform and learn together with your friends!