Question

what are the solutions of the quadratic equation 2x^2-16x+32=0?

Answer 1

Do you have any idea where to start?

Answer 2

honestly no.....

Answer 3

Okay, first, we can simplify the expression by removing a 2.

Answer 4

We would then have the equation:\[2(x ^{2}-8x+16)\] right?

Answer 5

*
=0

Answer 6

So, now we can split the x^2-8x+16 into the two groups. What do you see that makes a 16 through multiplication and an 8 through addition/subtraction?

Answer 7

WAIT I think i got it !!!!!
can you check my work?

Answer 8

Of course!

Answer 9

2x2 – 16x + 32 = 0
2(x^2-8x + 16) = 0
(x^2-8x+16) = 0
(x^2-4x -4x + 16) = 0
(x(x-4)-4(x-4)) = 0
(x-4)(x-4) = 0
(x-4)^2 = 0
(x-4)^2 = 0
x - 4 = 0
x = 4

Answer 10

Whoo! Good job! It's correct!

Answer 11

YAAAAy thank you! :D

Answer 12

Your welcome! Any time.