Question

y= 3^x lnx
can someone help me find the derivative please?

Answer 1

lookup product rule

Answer 2

yes i understand that but I'm sort of confused on how to find the derivative of 3^x

Answer 3

use this rule

If \[\Large y = b^x\]
then
\[\Large \frac{dy}{dx} = b^x*\ln(b)\]

Answer 4

notice that if b = e, then you'll have

y = e^x

become

dy/dx = e^x*ln(e) = e^x

Answer 5

so then it would be 3^x* ln(3) ?

Answer 6

yes

Answer 7

so would my final answer be 3^x/x + lnx * 3^x *ln(3) ?

Answer 8

I think you mean

\[\Large \frac{dy}{dx} = \frac{3^x}{x} + \ln(x)*3^x*\ln(3)\]

right?

Answer 9

yes

Answer 10

you are correct

Answer 11

okay thank you :)

Answer 12

np