Question

Given a and 1/2 are the roots of the quadratic equation 2x^2+px-3=0, find the values of a and p. see whether my working is correct. @ganeshie8

Answer 1

\[2(\frac{ 1 }{ 2 })^2 + p(\frac{ 1 }{ 2 })-3=0\]\[\frac{ 1 }{ 2 }+\frac{ p }{ 2 }-3=0\]\[\frac{ p }{ 2 }=\frac{ 5 }{ 2 }\]\[2p=10\]\[p=5\]

Answer 2

\[a=-\frac{ 3 }{ 2 }\div \frac{ 1 }{ 2 }\]

Answer 3

\[a=-3\]

Answer 4

@ganeshie8

Answer 5

Excellent! looks perfect!

Answer 6

there is another way to solve this problem if you know the sum of roots and product of roots stuff

Answer 7

2x^2+px-3=0

a and 1/2 are roots

product of roots = a*1/2 = -3/2
so a = -3

sum of roots = -3 + 1/2 = -p/2
so p = 5

Answer 8

Oh I see you're already using product of roots to solve a :)

Answer 9

this working is faster and neat :) thnx @ganeshie8

Answer 10

yw:)