Question

What is the solution of the following system?
(attachment)

Answer 1

Have you done anything? Also what methods are you allowed to use?

Answer 2

Multiply the first equation by 3 then add them to cancel out and solve for your terms.

Answer 3

is that two problems or just one full problem

Answer 4

1 problem.

Answer 5

name of lesson

Answer 6

so i multiply them and I get 9x+9y=30

Answer 7

then add what?

Answer 8

so 3x+3y=10 is that the first problem

Answer 9

its all one problem?

Answer 10

ok i am using http://www.freemathhelp.com/ to solve this

how would it look like

Answer 11

it look just like it does in the attachment

Answer 12

what grade is this

Answer 13

I'm in algebra 2

Answer 14

\[{3x+3y}=10\]

Answer 15

and then you can to the answer -9x-9y=-30 correct i need to know so i can give you the answer

Answer 16

y > 3x + 1

First, find the line y = 3x + 1. Some points are (0,1), (1, 4), (2, 7). Draw this line as a hash mark, since the inequality is >, not >=.

y <= (-2/3)x + 4. Some points on this line are (0,4), (1, 3 1/3), (2, 2 2/3). You will find that the two lines meet at (9/11, 3 5/11). This line should be drawn solid, since the inequality is <=, not <.

Now shade in the area above the first line and below the second. This will be for x < 9/11.

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Yes, but in ASCII, write it 16x^2 - y^2. With a pencil you can use a superscript.

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y = -2x + 6

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y = (-2/3)x + b
-2 = (-2/3) * 6 + b
-2 = -4 + b
b = 2

y = (-2/3)x + 2



@bizzeizzy