Solve the system of equations. 4x+3y=13 y=-x+14
Alright, you can either solve it using substitution or elimination; do you have a preference, or is there a particular way you *have* to do this?
so you plug in x plus 14 for y and whats 14 times 3
negative x im sorry
Going to go with substitution; where \[(1) \ \ \ 4x+3y=13,\]\[(2) \ \ \ y = -x+14,\]Plug in (2) into 1: \[4x+3(-x+14)=13.\]
@Mendicant_Bias nope
Alright; do you understand how to solve it from what I've posted above? That last line should be easy to do.
i think
Alright, take a shot at it. Get x by itself on one side, and get everything else on the other side.
cant get it:(
Do you know how to add and subtract things?
well yeah
\[4x+3(-x+14)=13\]
Alright, when you look at that, what do you think you should first do? First step involves getting rid of those parentheses.
ok so you distribute the three that gives you -3x and 42 so (4x -3x+ 42 + 13)
add like terms so then you get 1x + 42=13
subtract 42 from 13
x=?
29
(If you give people the answer, they won't learn.) Glorm did the right thing, I'd answer his question.
x= -29
you can check your work by plugging in x
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