Question

Two high divers jump off different platforms at the same time. The height of the first diver, in feet, is given by f(x) = –16x2 + 9x + 67, while the height of the second diver is given by f(x) = –16x2 + 15x + 54, where x is the number of seconds after they jump.

When are the divers at the same height? Round to the nearest hundredth of a second.

Answer 1

You can set the two equations equal to each other b/c they represent the height of each diver and you're looking for when they're at the same height. :)
-16x^2 + 9x + 67 = -16x^2 + 15x + 54
When you add -16x^2 to both sides it cancels, so now you have:
9x + 67 = 15x + 54
Can you solve for x from here? :)
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Answer 2

yes thank you, ill try.

Answer 3

wait do i cancel out the x's first or the regular numbers?

Answer 4

You want to isolate x.
Combine Like Terms by subtracting 9x from both sides and subtracting 54 from both sides.
9x + 67 = 15x + 54
13 = 6x
Now divide both sides by 6 to solve for x.
x = approx. 2.17 seconds

Answer 5

thank you, so if i was rounding to the nearest hundreth the answer would be 2.20?

Answer 6

or 2.17

Answer 7

Well, I already rounded, Lol. It was 2.16 repeating, so it rounds to 2.17. :)