can someone help me with a few math questions?
whats the question?
One zero is clearly 0 to start with. Having 3 roots with a multiplicity of 2 is not possible when the highest power is 3 lol. 3 can't possibly be a root because it's all additions there. So it's c).
I cannot help with this one sorry. @rawmoli what grade are you in?
im in 10th but i struggle with math
thanks guys
I am in 8th
oh loool its okay
:-)
@AngusV can you help me with this one also. i have the answers from my teacher but he only did some of them and the workpad
I mean, you can go down the path of actually finding the roots but when you have all the answers in front of you just take them out one by one. a) It's evident that 0 is a root (you can see it's a common answer in all 4 options and if you plug it in it instantly results into zero) pro tip: If there's an x next to every number in your polinomial equation then 0 is surely a root. pro tip#2: if there's an x next to every number in your polinomial equation then the smallest power of x in that case gives you 0's order of multiplicity b) The largest power in your polinomial equation gives you the number of roots. Because x^3 is the highest one, it means you have 3 roots which means either * 1 root has an order of multiplicity of 2 and the other one has an order of multiplicity of 1 * each of the 3 roots has an order of multiplicity of 1 To have 3 roots with an order of multiplicity of 2 you'd have to have x^6 or something. c) You are left with options 2 and 3 in the answers, the only difference being that option 2 has 3 as a root while option 3 has -3 as a root. Either notice or just plug it in and see that when you add: something positive + something positive + something positive You can't have that equal to 0. You need some negative numbers around so of course -3 is the fair intuitive answer on this one.
For the second one - it's d).
yea i knew it was d i just second guessed it
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