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Mathematics 8 Online
OpenStudy (anonymous):

someone please help asap. WILL GIVE MEDAL AND FAN!

OpenStudy (anonymous):

Give me a sec to post the question

OpenStudy (anonymous):

OpenStudy (anonymous):

@mathslover @camerondoherty @mathbrain77 @SolomonZelman

OpenStudy (solomonzelman):

lets exclude 2 options, knwoing that there is only the "SAS Similarity theory" exists, and nothing the "AA Similarity theory" does NOT exist.

OpenStudy (anonymous):

ok

OpenStudy (solomonzelman):

"SAS Similarity theory" exists. "AA Similarity theory" does NOT exist. which answer choices do you exclude?

OpenStudy (anonymous):

the 3rd and 4th choices

OpenStudy (solomonzelman):

yes, there you go

OpenStudy (anonymous):

oh okay, but why exclude the AA similarity theorem?

OpenStudy (anonymous):

and could the answer be the second option?

OpenStudy (solomonzelman):

because if 2 angles are similar (in 2 triangles) that doesn't necessarily make them equal.

OpenStudy (anonymous):

oh okay

OpenStudy (solomonzelman):

wait now, the imilarity theorem does exist.

OpenStudy (solomonzelman):

similarity, does exist, but the congruence isn't there. Sorry.

OpenStudy (solomonzelman):

the triangles are proportional by AA similarity theorem, so lets no exclude C and D

OpenStudy (solomonzelman):

you are proving that: Okay, you are proving that \(\large\color{black}{ ~ {\rm BC}^2= {\rm AB}^2+{\rm AC}^2 }\)

OpenStudy (solomonzelman):

so you want to prove that it is just a right triangle, not that they are equal.

OpenStudy (anonymous):

right

OpenStudy (solomonzelman):

the SAS similarity theorem is not applicable, because any of the smaller triangles is NOT equivalent to the entire, big, triangle.

OpenStudy (solomonzelman):

SAS would be showing congruence, which is not true here

OpenStudy (anonymous):

would choices a and c be excluded because triangle ADC is a right triangle, but triangle BAC isn't?

OpenStudy (solomonzelman):

so instead of excluding C and D, we actually come to that it is only C or D. (exclude A and B) yes A and B are not there...

OpenStudy (anonymous):

so could the answer be choice d?

OpenStudy (anonymous):

@SolomonZelman ?

OpenStudy (solomonzelman):

now, you have to prove, again \(\large\color{black}{ ~ {\rm BC}^2= {\rm AB}^2+{\rm AC}^2 }\) that means that you are proving a similarity of the smaller of the triangles to the biggershape.

OpenStudy (solomonzelman):

I have to depart to calculate something for the business. sorry

OpenStudy (solomonzelman):

i HAD, not have. I am back.

OpenStudy (anonymous):

okay, well thanks for your help!

OpenStudy (anonymous):

oh ok

OpenStudy (solomonzelman):

it is C. becuase you are proving that the big shape is similar to one of the smaller ones.

OpenStudy (solomonzelman):

D would be just proving how the smaller inner triangles are similar, and we don't need that

OpenStudy (anonymous):

I think I understand it now. Thanks!

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