Question

A container holds a combination of nickels and quarters. There are 156 coins in all, and their total value is $21.60. The system of equations models this situation, where x is the number of nickels and y is the number of quarters.

http://static.k12.com/bank_packages/files/media/mathml_0042740192549d14d857dce7de70145456a5e19b_1.gif

How many nickels and quarters are in the container?

A.
118 nickels and 38 quarters

B.
106 nickels and 50 quarters

C.
87 nickels and 69 quarters

D.
72 nickels and 84 quarters

Answer 1

explain y plz

Answer 2

@AlexandervonHumboldt2 plz help me

Answer 3

jay yay

Answer 4

sorry wrong person you both have dark pics hey @iGreen.

Answer 5

plz help

Answer 6

Solve for 'x' in the first equation:

x + y = 156

Subtract 'y' to both sides:

x = -y + 156

Now we can plug in -y + 156 for 'x' in the 2nd equation.

\(0.05(-y + 156) + 0.25y = 21.6\)

Distribute 0.05 into the parenthesis:

\(-0.05y + 7.8 + 0.25y = 21.6\)

Answer 7

Can you do the rest?

Answer 8

Add -0.05 + 0.25, what do you get?

Answer 9

0.2

Answer 10

Yes, that gives us:

\(0.2y + 7.8 = 21.6\)

Now subtract 21.6 - 7.8

Answer 11

13.8

Answer 12

Yep, that gives us:

\(0.2y = 13.8\)

Now divide 13.8 / 0.2.

Answer 13

69

Answer 14

so C?

Answer 15

thank you so much

Answer 16

100%

Answer 17

Yep, C is correct.

Answer 18

thanks @iGreen.