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Mathematics 18 Online
OpenStudy (anonymous):

WILL GIVE MEDAL AND FAN!!! What equation is graphed in the link? http://static.k12.com/eli/ecollege/543/7_29458/2_30741_7_29466/15cd71a370ac4e96f04d37b48ab0701e652ba48c/media/5e6a0c0d58daebf970dcca9515e27f68ee130a9e/mediaasset_308804_1.gif

OpenStudy (anonymous):

is it the same topic as before?

OpenStudy (anonymous):

yes @ChiefArnav

OpenStudy (anonymous):

do you remmeber the formualla may be it might be helpfull

OpenStudy (anonymous):

@iGreen.

OpenStudy (anonymous):

sure...

OpenStudy (anonymous):

@Nnesha

OpenStudy (anonymous):

Step 1: First of all we require starting points say (x1, y1) and ending points (x2, y2) of line. Now calculate the Slope of line. We have a formula to get the slope of line: m = (y2 - y1) / (x2 - x1), Assume that we have the coordinates (2, 0) and (-1, 3) then slope of line will be: m = (3 - 0) / (-1 - 2) = -1, Step 2: Now we will calculate the y- intercept. We will multiply the slope of line with starting 'x' point and subtract it from the starting 'y' point as: y intercept = 0 - (-1) * 2 = 2. Step 3: Now as we know that equation of line is y = mx + c. Here 'm' is the slope of line and 'c' is the y- intercept of line. We have already calculated 'm' and 'c' of line. Now we will place these values in line equation. Y = mx + c, Y = -x + 2, Step 4: If we want to verify the equation we can put the coordinates in equation and verify it. 0 = -2 + 2 = 0 and, 3 = 1 + 3 = 3.

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