Functions :) Homework problem. f(x) = 2x + 3 and g(x) = 9x - (1/2). Solve for f(14). I know how to solve it (the output of g(x) = the input of f(x)) but I forgot how to start... Is it by substituting 14 for x in g(x)? Can't remember.
well the question seems to ask for f(14) so substitute x = 14 into f(x) = 2x + 3 hope that makes sense
So i'm thinking it's going to start like this? \[f(g(x)) = f(g(14))\] \[f(x()) = f(9(14) - (1/2))\] And that's how you start it? i can solve from there.
or is the question 1. g(f(14)) ? or 2. f(g(14)).?
Well my teacher wrote it by hand so he might have meant find g(14)?
If he wanted me to find f(14) it wouldn't make sense to give me the g(x) equation so i think he meant to say find g(14).
that's correct... but then it could have been included as a distraction... my advice... find g(14) then substitute the value into f(x) and also find f(14) and then substitute it into g(x) that covers most options
Good plan. But back to the original question -- I forgot how to start out, so is my first statement correct? (as in f(g(x)) = f(9(14) - (1/2))
that's correct...
Ok then, so... \[f(125.5)\] \[f(g(x)) = 2(125.5) + 3\] \[f(g(x)0 = 254\]
There's an abstract zero in there o.O didn't mean to put that. Thanks camp!
that's great well done
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