Question

A referee tosses a coin straight up with an initial velocity of 19 ft per second from a height of 6 ft. What is the maximum height of the coin? if he doesnt catch it when will it hit the ground?

Answer 1

@AnswerMyQuestions @Data_LG2 @mathmate @math&ing001

Answer 2

Maximum height is given by \(h=\large \frac{v^2}{2g}\).
You can get the formula by equation potential and kinetic energies.
A free fall object starting from rest follows the rules:
Going up:
v=u+at (v=final velocity, u=initial velocity)
Here u=19, v=0, a=-9.8
Solve for t.
Going down,
S=ut+(1/2)at^2 (S=distance travelled)
Here,
u=0 (falling from rest)
a=-9.8
S=-(h+6) (use h calculated earlier)
Solve for t.
Add together the two t's to get total time.