Question

What are the possible number of positive, negative, and complex zeros f(x)=4x^3 + 2x^2 + 10x -5

Answer 1

\[3\sqrt{?}5625\]

Answer 2

demonstrate how to determine the number of positive,negative, and complex zeros f(x)=4x^3 + 2x^2 + 10x -5

Answer 3

zeyatic and heres the answer and tell me if that answers ur question
If you add a positive number and a negative number, and the positive number is larger (in absolute value) than the negative number, then the sum is positive. For example, 7 + (-5) is the same thing as 7 - 5 which equals 2. Adding a negative number is equivalent to subtracting a positive number. If the two numbers are the same (in absolute value) then the sum is zero. You will be subtracting a number from itself. And finally, if the negative number is larger (in absolute value) than the positive number, then the sum is negative. In other words, you have more negative than positive so you end up with negative. It's pretty simple. An example would be, 3 + (-4) which equals 3 - 4 which is -1.

Answer 4

Note that, since:
(a) f(x) = 4x^3 + x^2 + 10x - 14
(b) f(-x) = -4x^3 + x^2 - 10x - 14,

we see that f(x) has one sign change and f(-x) has two sign changes. By Descartes' Rule of Signs, f(x) has one positive real zero and either two or zero negative real zeroes. Since f(x) is of degree 3, there are either zero or two complex zeroes if there are two or zero negative real zeroes, respectively.

I hope this helps!

Answer 5

@zeyatic its here!!!