Question

Write a polynomial function with the given roots: 1 , -2 and 3i
Be sure to show your work when writing equation.

Answer 1

@Agl202

Answer 2

@siearra

Answer 3

Sorry, not sure about this one, @zeyatic

Answer 4

lol It's a little odd.

Answer 5

Complex roots always come in "pairs" - there's never a "solitary" complex root if I can put it that way. If a polynomial admits one complex root it also admits its conjugate.

Therefore, your polynomial should have a minimum of 4 roots, these being 1,-2,3i and -3i.

Working on that, we may construct our polynomial based on the general form of polynomials:

P=a*(x-root1)*(x-root2)*.... , so forth depending on how many roots you have.

where a is just about any constant except for 0 (duh) - although it could be if you want to be arrogant and call 0 a polynome.

P=a*(x-1)*(x+2)*(x-3i)*(x+3i) in our case.

where a can be just about anything (let it be 1 in this case)

P=(x-1)*(x+2)*(x^2+9)
P=(x^2+x-2)*(x^2+9)

You work the final form.

Answer 6

WoW great job, dude. I have learned something new today... Thanks for helpin him... ; )

Answer 7

No problem lol polynomials are fascinating.

Answer 8

Lol : )

Answer 9

can you plz do that last part

Answer 10

The last part is just about opening the parenthesis. Take each term from the left parenthesis and multiply it with each term of the right parenthesis.