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Mathematics 9 Online
OpenStudy (anonymous):

Check my answer? List possible roots for the equation 3x^4 - 5x^2 + 25 = 0 A. +1, +5, +25 B. +1, +1/3, +5, +5/3, +25, + 25/3 C. +1, +3 D. +25/3 I think it's A

OpenStudy (anonymous):

are u sure u write it correctly? i mean the question

OpenStudy (anonymous):

just take one of the root instead of x there will be no answer

OpenStudy (anonymous):

Yes its written exactly how the question is asked @M_A

OpenStudy (anonymous):

but there is no answer could u tell me how u find A?

OpenStudy (anonymous):

the school wouldn't give me a question there is no answer to

OpenStudy (anonymous):

i'm really sorry maybe i dont get your question

OpenStudy (mathmate):

To start, this is a quartic, so you cannot have 6 roots. The product of the roots must equal 25/3, and in no case it satisfies that, even if we assume double roots somewhere. You may have mismatched the question and the answer. @JoeJoldin I have to agree with @M_A.

OpenStudy (anonymous):

thanks mathmate

OpenStudy (freckles):

it says possible roots they are using that one test.. what's it called rational root test

OpenStudy (freckles):

thought the wording of the question is weird

OpenStudy (freckles):

because it doesn't say list the possible rational roots

OpenStudy (freckles):

it says list the possible roots

OpenStudy (freckles):

but based on the choices it looks like it wants us to apply that rational root test/theorem whatever it is called

OpenStudy (freckles):

you find the factors of the coefficient with least degree and find the factors of the coefficient with most degree the possible rational zeros will be: the factors of the coefficicent with least degree union the factors of the coefficient with least degree over the factors of the coefficent with most degree

OpenStudy (freckles):

and I bet she means + or -

OpenStudy (mathmate):

Yes, I agree, you read the question right. "Possible" roots is the key. So use the rational root theorem!

OpenStudy (anonymous):

Yes I need the rational roots please

OpenStudy (freckles):

for example if you have 10x^3-x^2-14x+4 you find factors of 4: (image I say + or - on each of these numbers ) 1,2,4 find factors of 10: (image I say + or - on each of these numbers) 1,2,5,10 the possible rationals are therefore (image I say + or - on each of these) 1,2,4,1/2,1/5,1/10,2/5,4/5,2/5 All I did was exactly what I said above (and I maye reduced)

OpenStudy (freckles):

oops don't need to list 2/5's twice

OpenStudy (freckles):

you already found the factors of 25 you need to find the factors of 3 the answer will be the factors of 25 union the factors of 25 over the factors 3

OpenStudy (anonymous):

So the answer is B? @freckles

OpenStudy (freckles):

B is definitely tons cute to me

OpenStudy (anonymous):

so...yes? @freckles

OpenStudy (anonymous):

@freckles

OpenStudy (mathmate):

@JoeJoldin According to the rational root theorem, the possible roots are: \(\pm \frac{possible~factors~of~the~constant~term}{possible~factors~of~the~leading~coeefficient}\) Leading coefficient is the coefficient of the hightest power of the polynomial. Example: The possible roots of \(6x^2-x-15\) are \(\pm\frac{1,2,3,6}{1,3,5,15}\) for a possible total 32 possibilities, such as 1/1,1/3,1/5,1/15,2/1,2/3,2/5,2/15,3/1,(3/3),3/5,(3/15),6/1,(6/3),6/5,and (6/15), all have either plus or minus.

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