Question

Curium-243 has a half-life of 28.5 days. In a sample of 5.6 grams of curium-243, how many grams will remain after 12 days?

Answer 1

would i just divide 5.6 by 2?

Answer 2

you can use the model
y = 5.6 ( 1/2) ^(t/28.5)

Answer 3

so i would do 2.8^t/28.5? @perl

Answer 4

not quite, order of operations :)

Answer 5

i still get 2.8^t/28.5 any way i do it. what am i doing wrong? @perl

Answer 6

you are multiplying 56 and 1/2

Answer 7

you are multiplying 5.6 and 1/2

Answer 8

i did that, and got 2.8.

Answer 9

y = 5.6 ( .5) ^(t/28.5)

Answer 10

plug in 12 for t

Answer 11

type into your calculator
5.6 ( .5) ^(12/28.5)

Answer 12

oh i understand what you meant by order now lol

Answer 13

i came up with 1.18 @perl

Answer 14

i divided 12 by 28.5
then i multiplied that by.5
then again by 5.6
@perl

Answer 15

^ means power

Answer 16

draw button died

Answer 17

okay, so .5 to the power of .421?

Answer 18

yes

Answer 19

.5^.421=.74690672855 so
7.5

Answer 20

and then multiply by 5.6

Answer 21

thank you, i got it