Question

Will give medal i need help please!!
2. A rectangular barge 6 m long and 3 m wide floats in fresh water. How much will the barge sink when loaded with 600 kg of sand?
i have no idea how to figure this out

Answer 1

@ganeshie8 @Destinymasha @ghuczek @gxldmouth @roha @JFraser

Answer 2

Buoyancy = weight of displaced fluid.
density = mass / volume
apparent immersed weight = weight - weight of displaced fluid

density of object/ density of fluid = weight/ weight of fluid


Give a try !! this is the best what i can get :D :p

Answer 3

i still dont get it

Answer 4

You need to pose equilibrium of forces:
\[\sum_{1}^{n}F=B-W=0\rightarrow B=W\] where \[W= weight= mg =600kg.9.8\frac{ m }{ s ^{2} }\]\[B= buoyancy= \rho.g.v=\rho.g.(h.l.w)=1000\frac{ kg }{ m ^{3} }.9,8\frac{ m }{ s ^{2} }.(h.6m.3m)\]
so:\[W=B \rightarrow mg=\rho.g.v \rightarrow v=\frac{ mg }{ \rho g }\rightarrow h=\frac{ mg }{ \rho glw }\]
and finally:\[h=\frac{ 600kg.9.8\frac{ m }{ s ^{2} } }{ 1000\frac{ kg }{ m ^{3} }9,8\frac{ m }{ s ^{2} }.6m.3m }=\frac{ 5880\frac{ kg.m }{ s ^{2} } }{ 176400\frac{ kg }{ s ^{2} } }=\frac{ 1 }{ 30 }m\]

Answer 5

I hope this helps