Question

divide: 36xy-397/3y explain

Answer 1

@DanJS

Answer 2

so i change the negative sign to a positive?

Answer 3

k

Answer 4

wait how do i clt if you have to divide 3?

Answer 5

are both terms divided by 3y or just the second?

Answer 6

well whatever the sum for the numerator is, is supposed to be divided by 3

Answer 7

divide each term in the numerator by \(3y\)

Answer 8

so do i go -362/3???

Answer 9

\[\frac{ 36xy - 397 }{ 3y } = \frac{ 36 }{ 3 }*\frac{ xy }{ y } - \frac{ 397 }{ 3 }*\frac{ 1 }{ y }\]

Answer 10

\[\frac{36xy-397}{3y}\]That is the question, yes?

Answer 11

divide the numbers and the variables separately like above

Answer 12

well 36-397 = -361

Answer 13

You cannot do that.

Answer 14

Big nono.

Answer 15

36/3 = 6
(xy)/y = x
397/3 = 397/3

Answer 16

ohh okay i divide each by 3....

Answer 17

yes,

Answer 18

Remember before, you can only add terms that have the same powers on the x

Answer 19

36/3=12
397/3=132.3

Answer 20

Keep the fractions that do not simply as fractions instead of decimals unless otherwise asked

Answer 21

simplify*

Answer 22

im confused.....

Answer 23

So leave \(\dfrac{397}{3}\) alone.

Answer 24

okay so 36/3=12 still

Answer 25

Yes.

Answer 26

\[\frac{ 36xy }{ 3y } = \frac{ 36 }{ 3 }*\frac{ xy }{ y } = 3 * \frac{ x*y*y ^{-1} }{ 1 } = 3 * x*y ^{1-1}\]

Answer 27

3x for that one

Answer 28

12x... lol i cant divide

Answer 29

:P

Answer 30

omg i forgot about the 1-1 lol

Answer 31

yes if you are dividing variables to pwers, just remember if you move one to the other side of the fraction, subtract its power

Answer 32

\[\frac{ y^6 }{ y^3 } = y ^{6-3} = y^3\]

for example

Answer 33

I would go about it this way:\[\frac{36xy-397}{3y}\]\[\left(\frac{\color{blue}{36}x\color{red}y}{\color{blue}{3}\color{red}{y}}\right)-\frac{397}{3y}\]

Answer 34

So simplify the blue, simplify the red, and you're done.

Answer 35

im goin to play skyrim.... later

Answer 36

xD

Answer 37

Whichever method makes sense to you, stick to it and solve it.

Answer 38

So for my method (36/3) = 12, right?

(y/y) = 1, yes?

Answer 39

\[\left(\frac{\color{blue}{36}x\color{red}y}{\color{blue}{3}\color{red}{y}}\right)-\frac{397}{3y} = 12x -\frac{397}{3y}\]