What is the slope of the line shown in the graph? A) 3/2 B) 2/3 C) negative 3/4 D) negative 2/3
@epicjackal117
@satellite73
@Hero
Do you know how to find the slope of an equation? It is equal to: \[\frac{y_1-y_2}{x_1-x_2}\] Where: \((x_1,y_1)\) is One Point on the line \((x_2,y_2)\) is another Point on the line
What we need to do is to pick to points to use in the equation. I will choose: (-3,5) and (3,1)
how do you know witch one is 1 and 2
The beauty is, it doesn't matter. You can make (1,2) as \((x_1,y_1)\) and (2,4) as \((x_2,y_2)\) OR, you can make (2,4) as \((x_1,y_1)\) and (1,2) as \((x_2,y_2)\) It doesn't matter what you choose for 1 and 2 :)
ok then how do we find the answer
What we need to do is to pick to points to use in the equation. I will choose: (-3,5) and (3,1)
ok
Click on the image to see the points I chosen I will make \((-3,5)=(x_1,y_1)\) \((3,1)=(x_2,y_2)\) Now, put these values into the equation: \[m=\frac{y_1-y_2}{x_1-x_2}\]\[m=\frac{5-1}{(-3)-3}\]\[m=\frac{4}{-6}\]\[m=\frac{2}{-3}\]\[m=-\frac{2}{3}\] Therefore the slope, or \(m\), is \(-\frac{2}{3}\]
Therefore the slope, or m, is \(-\frac{2}{3}\)
ok can you do another
@Ahsome
Sure, just close this equation and make another, @NunChuckBoy3101 :)
k
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