FAN + MEDAL!
Charlie’s Car Rentals charges a flat fee of $20 plus $24/day to rent a car. Jerry’s Car Rentals charges $28/day with no flat fee. The system that models this situation is given, where c is the cost of renting a car and d is the number of days a car is rented. c = 20 + 24d c = 28d The solution to the system is (5, 140). Which interpretation correctly describes the solution to the system of equations? A. The cost to rent a car is the same, $140, for both car rental companies if you rent a car for 5 days. B. The cost to rent a car is the same, $5, for both car rental companies if you rent a car for 140 days. C. Company A will charge more money on the fifth day by charging $140. D. Company A will charge less money on the fifth day by charging $140.
A. This is because \(5,140\) Is the answer when you use solve both of those equations. That means, at 5 days, both will cost $140. There is no other point where the cost and days will be the same between the two fees. So, it is A, where in \(5\) days (x value), the cost will both be \(140\) (y-value). If you would like to try it for youself, solve: \[c = 20 + 24d\]\[c = 28d\] Try it, and you will get 140 for \(c\) and 5 for \(d\) \[20+24d=28d\]\[20=4d\]\[d=\frac{20}{5}\]\[d=5\] \[20+24d\]\[=20+24\times5\]\[=20+120\]\[=140\]
The last section is for \(c\) \[c=20+24d\]\[c=20+24×5\]\[c=20+120\]\[c=140\]
DOes that make sense, @Light&Happiness?
Thank you! I was wondering if it was A or not.
And you were right :)
Very detailed answer like I needed, thanks again. :)
No probs :)
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