Question

Simplify (x-2)(x+5)/ (x^2-25)
A. 6/25
B. (x-1) / (x-5)
C. (x-1)/ (x+5)
D. -4/25

Answer 1

@ELizabethL

Answer 2

do you know how to factor
\[x^2-25\]?

Answer 3

no

Answer 4

are you in 8th or 7th grade?

Answer 5

ok then time to learn it
it is always the case that
\[a^2-b^2=(a+b)(a-b)\] that is how you factor the difference of two squares

Answer 6

@ELizabethL 7th

Answer 7

no i am in eleventh
in your case
\[a=x,b=5\] so
\[x^2-25=(x+5)(x-5)\]

Answer 8

\[\frac{(x-1)(x+5)}{(x+5)(x-5)}\] cancel the common factor

Answer 9

that makes sense

Answer 10

(x-1)/ (x+5)

Answer 11

btw you had a typo in the question i think
you had \(x-2\) but your answer choices had \(x-1\) so i assume that it was really \(x-1\)

Answer 12

Yeah it was a type sorry and thanks

Answer 13

but your answer is wrong

Answer 14

how?

Answer 15

\[\frac{(x-1)\cancel{(x+5)}}{\cancel{(x+5)}(x-5)}\]

Answer 16

should be
\[\frac{x-1}{x-5}\]