Question

y = 2x + 4
2x - y = 6
Solve the system of equations using substitution.


A)
(2,8)


B)
(2,-8)


C)
(10,24)


D)
no solution

Answer 1

@Ahsome

Answer 2

Oh, substitution. Have you done this before?

Answer 3

i think its b or a

Answer 4

How did you get that?

Answer 5

hang on let me go over my work

Answer 6

K

Answer 7

i have no clue lol uhm d?

Answer 8

lol
Ok, lets see your two equations:
\[y=2x+4\]\[2x-y=6\]

Now, since you haven't done this, bear with me. In the first equation, we have \(y\) by itself on the left hand side. Now, I want to do the same thing for the second equation. It will be apparent soon why I want this. Lets just do this:
\[2x-y=6\]\[-y=6-2x\]\[y=-1(6-2x)\]\[y=-6+2x\]

Now, you can see, we have these two equations:
\[y=2x+4\]\[y=-6+2x\]
Can you see how they both equal \(y\)? Since they both equal \(y\), they must both be equal as well! THerefore, we can say:
\[y=2x+4\text{ and }y=-6+2x\]
\[2x+4=-6+2x\]
Now, lets solve for \(x\)
\[2x+4=-6+2x\]\[2x+10=2x\]\[10=2x-2x\]\[10=0\]But thats impossible, since \(10\ne 0\)

Therefore, there is solution, since \(10\ne 0\), the answer is D :)

Answer 9

ok thank you so much will you help me with 2 more?

Answer 10

I will try, just got to eat lunch right now. After, I will, K?

Answer 11

If you thinked I help, please consider pressing the Best Response button, Thanks :)

Answer 12

lunch ok lol its 11 pm here and i will give you a medal

Answer 13

Thanks man :)

Answer 14

np