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Easy Limit !
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\[\lim_{x \rightarrow \infty}\frac{ \ln(x) }{\ln(1+x) }^{x*\ln(1+x)}\]
So is that exponent on the whole fraction or just ln(x)?
the whole fraction
@ganeshie8 @Abhisar @Callisto @Compassionate @uri @Kainui @eliassaab @inkyvoyd @Joel_the_boss @Coolsector
It's not as easy as it's long and annoying haha
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Is their a quick way to do this?
there*
I don't know that's why I posted this limit
Use \[\large \log_ay=x \implies a^x = y\] to start
mhm maybe \[\lim_{x \rightarrow \infty} \frac{ x \ln(1+x) \ln(\ln(x)) }{ \ln(ln(1+x)) } \implies \lim \lim_{x \rightarrow \infty} xln(1+x)\ln(\ln(x))-\ln(ln(1+x))\] to start
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Too lazy to fix the error haha
Then you'll have to take some derivatives
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