FAST LIMIT !
ok
\[\lim_{x \rightarrow \infty}(\frac{ x+15 }{ x+3 })^{\ln(\sin \frac{ 1 }{ x })}\]
@ganeshie8 @Abhisar @Callisto @Compassionate @uri @Kainui @eliassaab @inkyvoyd @Joel_the_boss @Coolsector @Amistre64 @TheSmartOne @bibby @geerky42 @confluxepic @inkyvoyd @Nnesha @camerondoherty @ParthKohli @Zale101 @poopsiedoodle
@Nnesha sorry It was a mistake
tried that e^ln thing and doing l'hopital ?
@ganeshie8 that method works all the time but it's very annoying I need something simpler
yeah i feel the same
the ln(sin(4/x) is power ?
ln(sin(1/x)) is the power
if you substitute the x in the sin you get when x-> infinte zero
ln (zero) = - infinite; (x+15/x+3) when x-> inifinite is 1;
1^-infinite = 1;
the answer is 1;
@borak 1^infinite is undetermination case believe me
O.K I will use the sandwich ; 1< the give data <lim x-> ininfte (x+15)/(x+3) ^ ln(1) you see sides is 1; then the give is 1 this good way
((x+15)/(x+3)) ^(ln(sin(4/x)) this bigger than 1; and if we found something bigger than ((x+15)/(x+3)) ^(ln(sin(4/x)) in limit equal to 1 then according to sandwich the give question will e in limit equal 1
\[\lim_{x \rightarrow \infty} (((x+15)/(x+3))^{\ln(1)} = 1\]
this is right side ; and left side is 1
then \[\lim_{x \rightarrow \infty} (((x+15)/(x+3))^{\ln(sin(4/x))} = 1\] between them !!! then he is equal in limit to 1
Can you prove me it's bigger than 1 ?
which one ?
@borak you found only the right side of the sandwich which is good but I need the left side which can't be 1 (it is a function which tends to be 1 but never it is like in the right side)
the number without the power is bigger that 1 you accept me in this point ?
actually tends to 1
from the right side it's tend yea ?
if it tends to 1 from the right then it's bigger than 1 , and equal to it in the limits
I don't understand what you saying|dw:1419101037171:dw|
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