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3 greater then or equal to x-4/2 + x/3 greater than or equal to 2 x belongs to integers.
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solve the inquation and graph it on a number line
@Nnesha
@ganeshie8
@Michele_Laino
@amistre64
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@Abhisar
multiply by 6 to get rid of the fractions is my idea
we have the subsequent steps: \[3\ge \frac{ x-4 }{ 2 }+\frac{ x }{ 3 }\ge2\] \[18\ge 3(x-4)+2x \ge12\]
then: \[18\ge5x-12\ge12\]
heh, i was reading it as an ending of 2x. i spose 3 to 2 is simpler to solve
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finally:\[6\ge x \ge \frac{ 24 }{ 5 }\]
hwo do i graph it?
I think in this way: |dw:1419101117747:dw|
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