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Mathematics 20 Online
OpenStudy (anonymous):

help

OpenStudy (anonymous):

Find the non-extraneous solutions of the square root of the quantity x plus 9 minus 5 equals quantity x plus 4.

OpenStudy (anonymous):

\[\sqrt{x + 9 } - 5 = x +4\] looks like this ^

OpenStudy (michele_laino):

ok! now please note that yor radicand has to be positive or equals to zero: namely\[x+9\ge 0\] or: \[x \ge -9\] so our non-extraneous solutions are those which are Greaterthan or equal to -9

OpenStudy (anonymous):

this is incase you want to see the multiple choice along with the question

OpenStudy (michele_laino):

now squaring both sides of your equation, I got: \[x+9=(x+9)^{2}\] so: \[(x+9)^{2}-(x+9)=0\] then: \[(x+9)[x+9-1]=0\] finally: \[(x+9)(x+8)=0\] Now if I apply the canceling law of product, I will get: x=-9, and x=-8 since both solutions check the inequality \[x \ge-9\] we can say that aour non-extraneous solutions are: x=-9, x=-8

OpenStudy (michele_laino):

so D. namely the fourth option

OpenStudy (anonymous):

Thank you so much and i wasn't sure about this because i'm not good in the square roots but i really appreciate your help

OpenStudy (michele_laino):

if there is something not clear, tell me, please!

OpenStudy (anonymous):

I will because your good at explaining so thank you

OpenStudy (michele_laino):

thank you!

OpenStudy (anonymous):

np :) okay i'm going to try to finish my homework and ill let you know if i need anything

OpenStudy (michele_laino):

ok!

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