help
Find the non-extraneous solutions of the square root of the quantity x plus 9 minus 5 equals quantity x plus 4.
\[\sqrt{x + 9 } - 5 = x +4\] looks like this ^
ok! now please note that yor radicand has to be positive or equals to zero: namely\[x+9\ge 0\] or: \[x \ge -9\] so our non-extraneous solutions are those which are Greaterthan or equal to -9
this is incase you want to see the multiple choice along with the question
now squaring both sides of your equation, I got: \[x+9=(x+9)^{2}\] so: \[(x+9)^{2}-(x+9)=0\] then: \[(x+9)[x+9-1]=0\] finally: \[(x+9)(x+8)=0\] Now if I apply the canceling law of product, I will get: x=-9, and x=-8 since both solutions check the inequality \[x \ge-9\] we can say that aour non-extraneous solutions are: x=-9, x=-8
so D. namely the fourth option
Thank you so much and i wasn't sure about this because i'm not good in the square roots but i really appreciate your help
if there is something not clear, tell me, please!
I will because your good at explaining so thank you
thank you!
np :) okay i'm going to try to finish my homework and ill let you know if i need anything
ok!
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