Question

For the given function, state the amplitude and the maximum output for the function:
ƒ(t) = 2sin(t).
A.) amp=2 max=4
B.) amp=4 max=4
C.)amp=4 max=2
d.) amp=2 max=2

Answer 1

The general sinusoidal function is

y = A * sin( 2pi / m ( x - p.s.) ) + v.s.

where A = amplitude
p.s. = phase shift
v.s. = vertical shift
m = period

Answer 2

Ive never heard of that function

Answer 3

@zepdrix sorry to bother you again but can you please explain this to me if you know how to do it cause Perl has confused me more. :/ Sorry

Answer 4

Hmm I'm not sure if I could explain it much better.
I think he gave you just a little bit too much information for this problem, so it's a bit of a brain overload hehe.

Answer 5

When we have this function,\[\Large\rm y=\sin t\]It's a periodic function,
it reaches a maximum output of 1,
a minimum output of -1,

and it repeats it's pattern over and over.

Answer 6

\[\Large\rm y=A \sin t\]As Perl said,
This A represents magnitude.
When a number is put in place of this A, it will change the maximum and minimum outputs of the function.

Answer 7

Oh i think i get it now. Perl just put it in big mathmatical sense.

Answer 8

He called it amplitude (blah sorry).
That makes more sense, since it's the letter A ;)

Answer 9

True

Answer 10

What do you think for this one?
Are there two options we can cross off immediately since we know the value of the amplitude?

Answer 11

b and c? right?

Answer 12

Good good good. So we narrowed it down to A or D.

Answer 13

Id say a.

Answer 14

no wait!

Answer 15

If \(\Large\rm y=\sin t\) has a maximum output of 1,
what will the new maximum output be if we multiply that by 2?

Answer 16

2?

Answer 17

1*2 = 2.
Good good good. :)

Answer 18

oh okays. Why did this happen to be super easy... -_- oh well Thank you again! Youre very kind :)

Answer 19

hehe

Answer 20

sorry i gave more info than you need. but keep that formula for later, it may come in handy