Given the function f(x) = 2(x − 1)2 + 1, indicate the shifts that will affect the location of the vertex and explain what effect they will have. Use complete sentences. f(x+3) f(x) + 3 f(3x) 3•f(x)
I'm very lost
your functions is \[f(x)=2(x-1)^{2} +1\] ???
The function is f(x) = 2(x − 1)^2 + 1
yes
anyone good at math im in 8th anyone above
f(x+3) = 2((x+3) - 1)^2 + 1
I just want to understand what I'm even doing.
f(x+3) = 2(x+2)^2 +1
see i just put in the (x+3) for the x ?
yeah
In the form f(x) = a*(x - b)^2 + c the b term shifts the graph sideways the c term shifts the graph up and down the a term streatches the graph or compresses it
So what tells me how the vertex changes?
So if you put in f(x+3) = 2((x+3) - 1)^2 + 1 you get f(x+3) = 2(x+2)^2 +1
In that case the b term is now -2 (x-(-2))
so you changed the b term by a +3
alright so what is the vertex in the equation or have we not even found it. I'm terrible at algebra.
it will move the vertex, the whole graph for that matter, sideways to the left by 3 units
Ohhh okay I get it now.
the standard "Vertex form is" y = a(x-h)^2 +k where (h,k) is the vertex point
so you get the first movement from the f(x+3) ?
so the question is I have to explain why it affects it and how it affects it.
you are putting in (x+3) into the equation wherever you see x
the standard form has (x - h) so if you add 3, it is the same as (x - (-3)) so that is moving the graph -3 in the x direction
(The vertex is the minimum or maximum in a quadratic eq) btw
Okay what tells us how much the vertex changes when we do this
how much the (h,k) changes in y = a(x-h)^2 +k
okay so now what is the (h,k) in the new equation
We have f(x) = 2(x − 1)2 + 1 f(x+3) = 2((x+3) - 1)^2 +1
so the h term changes from -1 to a +2, so the graph shifts to the LEFT by 3 units
(x - h) = (x -(-2)) = (x+2) the plus 2 means LEFT (x -(-2)) the h term is minus 2
so in summary, f(x+3) shifts the graph to the left 3 units
Thank you i get it now
the second is easier
f(x) + 3, you are going to add 3 to the k term in y = a(x-h)^2 +k
Shift the graph up by 3 units
f(x) + 3 = 2(x-1)^2 +1 +3 f(x) + 3 = 2(x-1)^2 + 4 (h,k) is the vertex, and the k value increased by 3 units, (SHift UP 3 units)
for f(3x), if you put that into your equation, you can see it will not effect either h or k, the graph will not be shifted, in this case it is compressed
3*f(x) , if you multiply the entire equation by 3, you see it will affect the a term and the K term, the graph will be compressed and shifted upwards
f(x) = a(x-h)^2 +k 3*f(x) = 3a(x-h)^2 +3k
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