Mathematics
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OpenStudy (anonymous):
@DanJS
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OpenStudy (anonymous):
i got 21
OpenStudy (danjs):
k 1 second
OpenStudy (danjs):
I remember solving this differential equation in class, the answer is
T(t) = A + C*e^(k*t)
Where C is a constant
OpenStudy (danjs):
you can separate variables like the last problem
OpenStudy (danjs):
what is T(0)?
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OpenStudy (danjs):
A = room temperature = 75
so
T(t) = 75 + C*e^(k*t)
OpenStudy (danjs):
T(0) = 180
T(10) = 100
OpenStudy (danjs):
so
OpenStudy (danjs):
T(0) = 180 = 75 + Ce^0 = 75 + C
180 = 75 + C
C = 180 - 75 = 105
OpenStudy (danjs):
Now we have:
T(t) = 75 + 105*e^(k*t)
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OpenStudy (danjs):
Use the next point you have to figure out the k value
OpenStudy (danjs):
T(10) = 100 = 75 + 105e^(k*10)
OpenStudy (danjs):
so k = -0.143508
T(t) = 75 + 105*e^(-0.1435*t)
OpenStudy (danjs):
If you put t=10 in there, you get 100
t= 0 in there , you get 180
OpenStudy (danjs):
How long will it take to cool to 80?
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OpenStudy (danjs):
80 = 75 + 105*e^(-0.1435*t)
OpenStudy (danjs):
For T(t) = 80 degrees ; t = 21.22 minutes
OpenStudy (danjs):
lol get all that
OpenStudy (danjs):
So yeah you were right initially, you said 21
OpenStudy (anonymous):
hahhaha thanks