Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (anonymous):

@DanJS

OpenStudy (anonymous):

i got 21

OpenStudy (danjs):

k 1 second

OpenStudy (danjs):

I remember solving this differential equation in class, the answer is T(t) = A + C*e^(k*t) Where C is a constant

OpenStudy (danjs):

you can separate variables like the last problem

OpenStudy (danjs):

what is T(0)?

OpenStudy (danjs):

A = room temperature = 75 so T(t) = 75 + C*e^(k*t)

OpenStudy (danjs):

T(0) = 180 T(10) = 100

OpenStudy (danjs):

so

OpenStudy (danjs):

T(0) = 180 = 75 + Ce^0 = 75 + C 180 = 75 + C C = 180 - 75 = 105

OpenStudy (danjs):

Now we have: T(t) = 75 + 105*e^(k*t)

OpenStudy (danjs):

Use the next point you have to figure out the k value

OpenStudy (danjs):

T(10) = 100 = 75 + 105e^(k*10)

OpenStudy (danjs):

so k = -0.143508 T(t) = 75 + 105*e^(-0.1435*t)

OpenStudy (danjs):

If you put t=10 in there, you get 100 t= 0 in there , you get 180

OpenStudy (danjs):

How long will it take to cool to 80?

OpenStudy (danjs):

80 = 75 + 105*e^(-0.1435*t)

OpenStudy (danjs):

For T(t) = 80 degrees ; t = 21.22 minutes

OpenStudy (danjs):

lol get all that

OpenStudy (danjs):

So yeah you were right initially, you said 21

OpenStudy (anonymous):

hahhaha thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!