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Mathematics 11 Online
OpenStudy (anonymous):

Geometry Help!

OpenStudy (alexandervonhumboldt2):

yes

OpenStudy (anonymous):

In ΔABC shown below, BD over BA equals BE over BC: Triangle ABC with segment DE intersecting sides AB and BC respectively. The flowchart proof with missing statements and reasons proves that if a line intersects two sides of a triangle and divides these sides proportionally, the line is parallel to the third side:

OpenStudy (anonymous):

@Abhisar

OpenStudy (anonymous):

@jim_thompson5910 Please Help!

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

Anyone?

OpenStudy (anonymous):

@kmorgan

OpenStudy (anonymous):

She is offline, why would you tag her lol

OpenStudy (anonymous):

idk

OpenStudy (anonymous):

@Ashleyisakitty

OpenStudy (anonymous):

@awkwardpanda @SolomonZelman @zepdrix

jimthompson5910 (jim_thompson5910):

notice how the second block has "side angle side similarity postulate"

jimthompson5910 (jim_thompson5910):

the proportion BD/BA = BE/BC takes care of the two "S"s for the sides you just need a statement and reason that helps with the angle portion

OpenStudy (anonymous):

1. ∠A ≅ ∠A 2. Reflexive Property of Equality 1. ∠A ≅ ∠B 2. Corresponding Parts of Similar Triangles 1. ∠A ≅ ∠B 2. Corresponding Angles Postulate 1. ∠B ≅ ∠B 2. Reflexive Property of Equality

jimthompson5910 (jim_thompson5910):

|dw:1419128066396:dw|

jimthompson5910 (jim_thompson5910):

break up the triangles |dw:1419128115390:dw|

OpenStudy (anonymous):

Okay

jimthompson5910 (jim_thompson5910):

|dw:1419128189319:dw|

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