Question

Find the vertices and foci of the hyperbola with equation (x+5)^2/81 - (y-3)^2/144 = 1.?

@wio sorry last question!

Answer 1

@watchmath

Answer 2

\(a^2+b^2=81+144=225=15^2\)
The vertex are at \((-14,0)\) and \((4,0)\). Hence the foci are at \((-14-15,0)=(-29,0)\) and \((4+15,0)=(19,0)\)

Answer 3

sorry it is wrong. Give me a minute

Answer 4

@watchmath that's okay! I understand the formula

Answer 5

The center is at \((-5,3)\). So the foci are at (-20,3) and (10,3)

Answer 6

so vertices at (4,3) and (-14,3)? @watchmath

Answer 7

yes

Answer 8

@watchmath THANK YOU SO MUCH! I think I get these problems now!(: