Write out the balanced equation for the reaction that occurs when Mg and Fe(NO3)3 react together.
it will be substition betwin \[Fe ^{3+} and Mg ^{2+}\]
@Abhisar
Have you learnt about substitution reaction?
No, I have learned double replacement
Here is the example they gave, Cu + 2AgNO3 \(\rightarrow\) Cu(NO3)2 + 2Ag, so would it be Mg(NO3)3 + Fe?
That is what I am thinking, but I am probably wrong :(
You are correct about skeleton structure of the equation. When you write the chemical formula of a compound like when you write \(\sf Fe(NO_3)_3\), you actually write the valency of each radical in the subscripts i.e 3 after the brackets in the subsript in \(\sf (NO_3)_3\) represents the valency of Fe. Similarly valency of \(\sf NO_3\) is written in the subscript in Fe. When no subscript is mentioned it means that the valency is 1 so the valency of \(\sf NO_3\) is 1 Now the skeleton structure of our equation as you said is following \(\sf Mg + Fe(NO_3)_3 \rightarrow Mg(NO_3)_\color{red}{?}+Fe\) Replace the ? with correct valency.
Wouldn't it be 3?
How? Whose valency is 3?
No, 2
\(\sf Mg + Fe(NO_3)_3 \rightarrow Mg(NO_3)_\color{red}{2}+Fe\)
Again how/why?
I'm not really sure, that was just one of the examples they gave in the lessons, but didn't explain it at all :(
Just explain what made you think it should be 2 so that I can know if you have understood it properly.
Because that is the number of valence electrons gained?
Read what I said you earlier again. To write a chemical formula say \(\sf Fe(NO_3)_3\) you just criss cross the valencies as following |dw:1419147390977:dw|
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