Question

Sam is observing the velocity of a car at different times. After two hours, the velocity of the car is 54 km/h. After four hours, the velocity of the car is 58 km/h.

Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points)

Part B: How can you graph the equation obtained in Part A for the first six hours? (5 points)
@ganeshie8 @perl

Answer 1

v=50+2t is part A correct?

Answer 2

were v is velocity and t is time

Answer 3

V=50+2t
V is velocity ..... T is time in hours!!!
Hope this helps!!! : )

Answer 4

but what is it talking about in standard form perl?

Answer 5

Great job @knightmare6!!!

Answer 6

and it says show your work

Answer 7

I think y = mx + b is fine for standard form

Answer 8

there is a special 'standard form' Ax + bY = C , but it doesn't seem appropriate here

Answer 9

okay but how did i get 50 i really dont know how i did

Answer 10

first find the slope

Answer 11

i did that

Answer 12

(2,54) and (4,58)

Answer 13

you are given two points (time , velocity)

Answer 14

right

Answer 15

which is y2-y1/x2-x1 which is 2

Answer 16

two ordered pairs , i should say

Answer 17

but now how do i get 50

Answer 18

right, so far you have
y = 2t + b

Answer 19

v=2t+b

Answer 20

you plug in either point and solve for b, the y intercept

Answer 21

or the 'v intercept'

Answer 22

so how do i do that

Answer 23

You are given :
After two hours, the velocity of the car is 54 km/h. After four hours, the velocity of the car is 58 km/h.

that means (2, 54) and (4, 58) are two points on the required graph and u can use these to write the equation for velocity in slope-intercept form

Answer 24

plug in (2,54) for x and y

Answer 25

54 = 2(2) + b

Answer 26

here x = t , y = v

Answer 27

oh okay i understand

Answer 28

:)

Answer 29

okay so now for Part B;

Answer 30

do i just plug 6 into t?

Answer 31

for part b you need to graph

Answer 32

i have just the program for that

Answer 33

Plug in 0 for t and then 6 for t...you get (0,50) and (6,62)
Connect those 2 points and you have your graph for the first 6 hours

Answer 34

Hope this helps ya!!! : )

Answer 35

https://www.desmos.com/calculator/zlsc4g9tsf

you have zoom out (scroll wheel down) to see the graph

Answer 36

@perl im confused

Answer 37

do i just plug in 0 and 6 for t?

Answer 38

you can make a table

Answer 39

or plug in 0 and 6 , yes , thats two values of the table

Answer 40

for 0-6?

Answer 41

for a line, 2 points are enough

Answer 42

but it doesnt hurt to plot more points , helps to draw it

Answer 43

so for part B i can say you can plug in 0 and 6 for t

Answer 44

Is that a yes or no

Answer 45

yes

Answer 46

Part B: `How can you graph` the equation obtained in Part A for the first six hours? (5 points)

Answer 47

you can pick t = 0, t = 6