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Mathematics 9 Online
OpenStudy (anonymous):

medal and please explain What is the simplified form of

OpenStudy (anonymous):

OpenStudy (danjs):

take the bottom fraction, flip it over and multiply it to the top

OpenStudy (danjs):

factor each term you are able to, then cancel out any common terms in the top and bottome

OpenStudy (anonymous):

can you please show me how?

OpenStudy (danjs):

ok...

OpenStudy (anonymous):

like how do i set it up

OpenStudy (danjs):

\[\frac{ (x^2+5x+6) }{ 15*x*y^2 }*\frac{ 5*x^2*y }{ 2x^2+7x + 3 }\]

OpenStudy (danjs):

Flip the bottom over and multiply instead

OpenStudy (anonymous):

so i basically multiply 15 times x times y^2 with the numerator?

OpenStudy (anonymous):

and the same with the other fraction?

OpenStudy (danjs):

all i did was take the bottom fraction, flip it over, and tagged it on as multiplication to the top fraction

OpenStudy (danjs):

now we need to simplify, you want to factor any of those polynomial terms you can

OpenStudy (danjs):

\[\frac{ (x+3)(x+2) }{ 15x*y^2 } \frac{ 5x^2 *y }{ (2x + 1)(x + 3 ) }\]

OpenStudy (anonymous):

wait this is where i get kind of confused. so i multiply across or something?

OpenStudy (anonymous):

or factor. how do i factor

OpenStudy (danjs):

Yes \[\frac{ a }{ b }\frac{ c }{ d } = \frac{ a*c }{ c * d }\]

OpenStudy (danjs):

to combine to one fraction

OpenStudy (danjs):

i factored the top and bottom in the last step,

OpenStudy (anonymous):

so the variable A would be 3? and B is 15?

OpenStudy (danjs):

\[\frac{ 5x^2y*(x+3)(x+2) }{ 15xy^2 * (x+3)(2x+1) }\]

OpenStudy (danjs):

no that was just to show you how to multiply fractions,

OpenStudy (danjs):

so there it is combined into one fraction

OpenStudy (anonymous):

so now i just simplify it down?

OpenStudy (danjs):

right

OpenStudy (danjs):

what would you do first?

OpenStudy (anonymous):

multiply 5 by 3?

OpenStudy (danjs):

no, for the numbers, you have \[\frac{ 5 }{ 15 } = \frac{ 1 }{ 3 }\]

OpenStudy (danjs):

reduces to 1 in the top and a 3 in the bottom

OpenStudy (anonymous):

ohhh

OpenStudy (danjs):

see the (x+3) is on both top and bottom, you can cross those out

OpenStudy (danjs):

x^2 / x goes to just x/1 y / y^2 goes to just 1/y

OpenStudy (danjs):

so all thogether it is.....

OpenStudy (danjs):

\[\frac{ x (x+2)}{ 3*y*(2x+1) }\]

OpenStudy (danjs):

That is all you can do to simplify

OpenStudy (danjs):

unless you want to multiply out the parenthesis, but i wouldnt

OpenStudy (anonymous):

thank you so much for explaining and helping

OpenStudy (danjs):

no prob, write all the steps i did down, you will see it more clear prolly

OpenStudy (danjs):

any more questions, feel free to mssg me or whatever

OpenStudy (anonymous):

alright. thanks!

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