medal and please explain What is the simplified form of
take the bottom fraction, flip it over and multiply it to the top
factor each term you are able to, then cancel out any common terms in the top and bottome
can you please show me how?
ok...
like how do i set it up
\[\frac{ (x^2+5x+6) }{ 15*x*y^2 }*\frac{ 5*x^2*y }{ 2x^2+7x + 3 }\]
Flip the bottom over and multiply instead
so i basically multiply 15 times x times y^2 with the numerator?
and the same with the other fraction?
all i did was take the bottom fraction, flip it over, and tagged it on as multiplication to the top fraction
now we need to simplify, you want to factor any of those polynomial terms you can
\[\frac{ (x+3)(x+2) }{ 15x*y^2 } \frac{ 5x^2 *y }{ (2x + 1)(x + 3 ) }\]
wait this is where i get kind of confused. so i multiply across or something?
or factor. how do i factor
Yes \[\frac{ a }{ b }\frac{ c }{ d } = \frac{ a*c }{ c * d }\]
to combine to one fraction
i factored the top and bottom in the last step,
so the variable A would be 3? and B is 15?
\[\frac{ 5x^2y*(x+3)(x+2) }{ 15xy^2 * (x+3)(2x+1) }\]
no that was just to show you how to multiply fractions,
so there it is combined into one fraction
so now i just simplify it down?
right
what would you do first?
multiply 5 by 3?
no, for the numbers, you have \[\frac{ 5 }{ 15 } = \frac{ 1 }{ 3 }\]
reduces to 1 in the top and a 3 in the bottom
ohhh
see the (x+3) is on both top and bottom, you can cross those out
x^2 / x goes to just x/1 y / y^2 goes to just 1/y
so all thogether it is.....
\[\frac{ x (x+2)}{ 3*y*(2x+1) }\]
That is all you can do to simplify
unless you want to multiply out the parenthesis, but i wouldnt
thank you so much for explaining and helping
no prob, write all the steps i did down, you will see it more clear prolly
any more questions, feel free to mssg me or whatever
alright. thanks!
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