Question

How many joules are needed to heat 48 grams of water from 10 degrees C to 96 degrees C? How many calories is this?

Answer 1

@ganeshie8

Answer 2

@wio

Answer 3

@Miracrown

Answer 4

Use \(\sf \color{red}{q=mc \Delta T}\)

q = heat
m = mass
c = heat capacity
\(\Delta\)T = change in temperature (the difference)

Answer 5

which numbers represent what in this case?

Answer 6

@Kainui

Answer 7

what is the heat capacity of water?

Answer 8

i don't know. i wasn't here to learn this topic

Answer 9

@Abb0t is correct.

Water has to absorb 4.184 Joules of heat for the temperature of one gram of water to increase 1 degree celsius (Specific Heat Capacity)

\[c = \frac{ 4.184 J }{ g * C^{\circ }} \]

Answer 10

As usual.

Answer 11

mass of 48 g, specific heat capacity above, change in temp of 86 degrees.

To convert that to calories... the approximate amount of energy needed to raise the temperature of one gram of water by one degree Celsius at a pressure of one atmosphere... use
1 cal = about 4.2 Joules

Answer 12

ahah, mad chemist, of course as usual

Answer 13

specific heat capacity for water = 4.18 J/(g*degC)
(how much energy is required per gram per change in degrees C)

mass = 48g
Change in temperature = 96-10 = 86 deg C

energy required = mass * change in temperature * specific heat capacity
= 48g * 86degC * 4.18 J/(g*degC)
=17255.04 J
1 calories =4.184 joules or 1 joules =0.239005736 calories
so 17255.04 *0.239005736=4124.05 calories