Question

Use natural logarithms to solve the equation.

6e2x – 9 = 23

Round to the nearest thousandth.

Answer 1

\[6e^{2x}-9=23\]?

Answer 2

yes

Answer 3

1) add 9

Answer 4

2) divide by 6

Answer 5

let me know when you get \[e^{2x}=\frac{16}{3}\]

Answer 6

e^2 x - 16/3 = 0

Answer 7

still wating

Answer 8

fan me so I can ask you a question

Answer 9

satellite73 can you answer the most recent question

Answer 10

From the step @satellite73 left off\[e ^{2x}=\frac{ 16 }{ 3 }\]Take the natural logarithm of both sides\[\ln e ^{2x}=\ln \frac{ 16 }{ 3 }\]Now use the appropriate properties of logarithms to simplify and solve for x. Remember\[\ln e =1\]