****************Probability***************** A bag contains five red chips, 3 blue chips, and 2 yellow chips. Two chips are selected from the bag, without replacement. Determine the probability that two chips of the same color are selected
gotta do it for each color
Oh can I give direct answers Oh right no sorry
i did for Red, I got 1/2 Blue, 3/10 Yellow, 1/5
hold on
but I don't know what to do after that
and alright thank you
start with yellow. That's the easiest
two red is not right probability first is red is \(\frac{1}{2}\) then the probability second is red given the first is red is \[\frac{4}{9}\] since there are 9 left and 4 red ones so probababiltyi both are red is \[\frac{1}{2}\times \frac{4}{9}=\frac{2}{9}\]
other two are similar once you get the other two, add them up
oh right I forgot to take into account that the chip wasn't put back
getting 2 blue is very similar, except you start with 3, not 5
for blue i got 1/15, and yellow 1/45
i didn't do it but i can check
1/15 is right
so is 1/45
you said to add them up at the end so i make all the denominators the same right?
yes of course or use a calculator but you can use a denominator of 45 for each
14/45?
yup
oh alright perfect thank you you helped alot!
yw glad to help
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