Question

Which equation has a diameter with endpoints (3,-2) and (-5,8)?

Answer 1

1. (x+1)^2+(y-3)^2=41
2.(x-1)^2+(y+3)^2=41
3. (x+3)^2+(y-2)^2=164
4.(x-3)^2+(y+2)^2=2 (square root of 41)

Answer 2

(x-x1)(x-x2)+(y-y1)(y-y2)=0

Answer 3

1. (x+1)^2+(y-3)^2=41?

Answer 4

(x-3)(x+5)+(y+2)(y-8)=0

Answer 5

1.siplify it.

Answer 6

my answer is wrong?

Answer 7

or find the middle points of the extremities of diameter,it is center.

Answer 8

yes i found midpoint which is -1,3 and i automatically picked 1.

Answer 9

your answer is correct

Answer 10

i was telling you other method.
second method is easy.

Answer 11

(x - h)^2 + (y - k)^2 = r^2

to find the radius r,
compute the distance between those two points and take half of that.
To get the center (h,k)
Use the midpoint of that diameter.