Rewrite this expression in the simplest radical form. (4x^3 y^4)^3/2
Do you cube this, and then find the square root of that? What's the rules here?
\[(a^bc^d)^e=a^{b \times e}c^{d \times e}\]
I know. I just want to know what the power of 3/2 translates too
\[(Aa^bc^d)^e=A^ea^{b \times e}c^{d \times e}\]
Would this be the square root of 4x^9 y^12
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3/2 translates to cubed then square rooted. but if you use the distributive rule for exponents I gave you you'll get the answer
you can take the square root first then cube it if you'd like. there's no difference
so my answer is correct then, right?
you have to cube the constant as well
its multiple choice the answer i gave was one of them. could it be even more simplified?
square root of (64 x^9 y^12) would be correct
8 x^(9/2) y^6 would be my answer
not an answer choice
2xy^2 times the square root of x 8x^4 y^6 times the square root of x the square root of 8x^6 y^7
what happens when you multiply say a^b and a^c ?
You can throw out (a) right away because 4^(3/2) you know is 8
\[\large a^b \times a^c = a^{b+c}\]
not quite getting it. there's a even more simplified version then my answer though right?
The most simplified version is the answer I gave
\[8x^{9 \over 2}y^6=8x^4y^6 \sqrt{x}\]
9/2 equal 4.5 which is 4 + 0.5. so using the other formula I provided for the multiplication of exponents with the same base, you get this answer
These are things you have to memorize and validate with a calculator. you can prove this by writing it all out if you want. Or you can memorize these rules
so .5= square root of x?
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