Question

please help

Answer 1

Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1.

f(x) = −1/2 (x − 6)^2 + 3/2
f(x) = 1/2 (x − 6)^2 + 3/2
f(x) = −1/2 (x + 3/2)^2 + 6
f(x) = 1/2 (x + 3/2)^2 + 6

Answer 2

please show your work so i understand how you got the answer :)

Answer 3

Did you already work out this problem?

Answer 4

let take a point \((x,y)\) on the parabola

so the point \((x,y)\) is equal in distance from the focus \((6,2)\)and the perpendicular
distance of directrix \(y=1\)

hence

\(\large\tt \begin{align} \color{black}{
\sqrt{(x-6)^2+(y-2)^2}=\left|y-1\right| \\~\\
\sqrt{(x-6)^2+(y-2)^2}=\sqrt{(y-1)^2} \\~\\
}\end{align}\)

Answer 5

shift y terms on left hand side and x terms on right hand side

Answer 6

sorry my computer shut down and i started working on other homework so i forgot about this but this is the last question to my test can you help me get the answer

Answer 7

and also i wasn't taught this because i missed something and my teacher is out on winterbreak

Answer 8

i already gave u 80% of the answer

Answer 9

i just don't know what to plug in i really want to learn how to do this but i don't understand anything (sorry i'm stupid)

Answer 10

ok u need to go to this for making it clear
http://www.mathsisfun.com/geometry/parabola.html

Answer 11

okay just give me a second im trying to read it

Answer 12

k nevermind i just figured it out i got a 100% on the test thank you though now i have to sleep it's 3 Am where i live goodnight