A container holds a combination of dimes and quarters. There are 178 coins in all, and their total value is $29.80. The system of equations models this situation, where x is the number of dimes and y is the number of quarters.
x+y=178
0.1x+0.25y=29.8
How many dimes and quarters are in the container?
A.
123 dimes and 55 quarters
B.
114 dimes and 64 quarters
C.
102 dimes and 76 quarters
D.
98 dimes and 80 quarters
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OpenStudy (anonymous):
Please help
OpenStudy (anonymous):
@mathmath333
OpenStudy (anonymous):
@Hero
OpenStudy (mathmath333):
u have the two given equations u have to solve them
\(x+y=178---(1)\\
0.1x+0.25y=29.8\\
\dfrac{x}{10}+\dfrac{25y}{100}=\dfrac{298}{10}\\
\text{multilying both sides by 100}\\~\\
10x+25y=2980\\~\\
\text{divide by 5}\\~\\
2x+5y=596-----------(2)\\~\\
\)
OpenStudy (anonymous):
so how would i find the answee
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OpenStudy (anonymous):
answer*
OpenStudy (mathmath333):
multilying\( (1) \)by \(-2\)
\(-2x-2y=-356-------(3)\)
add \((2)\) and \((3)\)
OpenStudy (anonymous):
I think it might be A or C
OpenStudy (mathmath333):
both are wrong
OpenStudy (anonymous):
B?
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OpenStudy (mathmath333):
can u add (2) and (3)
OpenStudy (anonymous):
5
OpenStudy (mathmath333):
lol i m asking about the equations (2) and (3)
OpenStudy (anonymous):
im really confused can u tell me the answer and then explain i think that would be easier
OpenStudy (mathmath333):
sry i cant tell the answer , its againts the rules
u need to solve these
\((2x+5y)+(-2x-2y)=596+(-356)\)
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OpenStudy (anonymous):
the problem is that i dont know how...
OpenStudy (mathmath333):
what is \(2-2\)
OpenStudy (anonymous):
0
OpenStudy (mathmath333):
what is \(2x-2x\)
OpenStudy (anonymous):
x
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OpenStudy (mathmath333):
no its \(0\), \(x\) can be any unknown number
OpenStudy (anonymous):
ok
OpenStudy (mathmath333):
just like \(2-2\)
OpenStudy (anonymous):
ok
OpenStudy (mathmath333):
and what is \(5y-2y\)
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OpenStudy (anonymous):
3y
OpenStudy (mathmath333):
good
so what will be
\((2x+5y)+(-2x-2y)=\)
OpenStudy (anonymous):
x-3y=249
OpenStudy (anonymous):
240*
OpenStudy (mathmath333):
\((2x+5y)+(-2x-2y)\\
=2x+5y-2x-2y\\
=3y\)
is that right
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OpenStudy (anonymous):
yes
OpenStudy (anonymous):
i think so
OpenStudy (mathmath333):
so
\(3y=240\)
\(y=\dfrac{240}{3}\)
OpenStudy (anonymous):
y=80
OpenStudy (anonymous):
so that means its D?
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OpenStudy (mathmath333):
ok
\(x+y=178\\
x+80=178\\
x=?\)
OpenStudy (anonymous):
?
OpenStudy (anonymous):
oh wait
OpenStudy (anonymous):
its D
OpenStudy (mathmath333):
u found \(x\) ?
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