Question

Can someone please help me? Don't do the work for me.. just help please!

Answer 1

1.Create a quadratic function, f(x), in vertex form. The a should be between 4 and –4, the h will be your birth month, and the k will be your birth day. Write your equation below.


2.Using complete sentences, explain how to convert your birthday function into standard form.


3.Graph your function. Include your graph below.


4.Using complete sentences, explain how to find the average rate of change for f(x) from x = 4 to x = 7.

Answer 2

my birthday is 6-25-97

Answer 3

what is the equation for vertex form?

Answer 4

y = a ( x - h)^2 + k

Answer 5

you can pick an easy 'a', let a = 1

Answer 6

now plug in h = # month, k = # birth day

Answer 7

\[1(x-2)^{2}+25\]

Answer 8

your birthday says month 6

Answer 9

that's what I meant.. whoops

Answer 10

no probs :)

Answer 11

I have to use complete sentences to explain how to get it in standard form... so \[ax ^{2}+bx+c\] ?

Answer 12

so you can expand that

Answer 13

(x - 6) ^2 + 25
= (x - 6)*(x-6) + 25
= x^2 - 6x -6x + 36 + 25

Answer 14

x2 -12x+61?

Answer 15

would the lowest point on my graph be -6?

Answer 16

what about....
4.Using complete sentences, explain how to find the average rate of change for f(x) from x = 4 to x = 7.

Answer 17

@swamijatin2

Answer 18

yes

Answer 19

how do I find an average rate of change? is there an equation?

Answer 20

I've done this question like 3 times..lol.

Answer 21

@blaizer1 Yes, we use the slope formula.

\(m = \dfrac{y_2-y_1}{x_2-x_1}\)

Answer 22

okay... lol the only problem is I don't have any ordered pairs .. I don't know what to put on my graph yet.....

Answer 23

This is your equation:

\(x^2 -12x+61\)

So we have to find out what y is when x = 4 and when x = 7.

First, plug in x = 4:

\(4^2 - 12(4) + 61\)

Now solve.

First we simplify the exponent.

\(16 - 12(4) + 61\)

Now we multiply -12 * 4:

\(16 - 48 + 61\)

Now we subtract:

\(-32 + 62\)

Add:

\(30\)

So our first point is (4, 30)

Can you do the same thing for x = 6?

Answer 24

wait would my order pairs be 4,16 and 7,49

Answer 25

Oops, made a mistake.

It's:

\(-32 + 61\)

\(29\)

Answer 26

Now plug in x = 6:

\(x^2 - 12x + 61\)

\(6^2 - 12(6) + 61\)

Can you solve that?

Answer 27

I got 25

Answer 28

oh I think instead of 6 I should have done 7?

Answer 29

25 is correct..and you're right, we should have done 7..lol my bad.

Answer 30

\(x^2 - 12x + 61\)

\(7^2 - 12(7) + 61\)

Answer 31

Tell me what you get.

Answer 32

so 26... so the ordered pair is 7, 26?

Answer 33

Yep, you got it

Answer 34

my rate of change is -1???? I plugged the ordered pairs in the slope form thingy... one more thing.... are there certain ordered pairs I put on my graph.. im not sure where to start.

Answer 35

So our two ordered pairs are (4, 29) and (7, 26).

Plug them in:

\(m = \dfrac{y_2-y_1}{x_2-x_1}\)

\(m = \dfrac{26-29}{7-4}\)

Now can you subtract those and divide?

Answer 36

Oh wait..

\(m = \dfrac{26-29}{7-4}\)

\(m = \dfrac{-3}{3}\)

\(m = -1~\Large\color{lime} \checkmark\)

Answer 37

You got it..

So the average rate of change from x = 4 to x = 7 is -1. :D

Answer 38

now for my graph.. do you know what ordered pairs I use?

Answer 39

You can use this graph:

https://www.desmos.com/calculator/8w7ardqezn

Just take a screen shot and cut it out if you want..