Combine the like terms to simplify the expression: 10xy2 + 5x – 4y3 + 6 – x + 5x2y + 6xy2 – 2 A. 10xy2 + 5x2y – 4xy3 + 4 B. 21xy2 + 4x – 4y3 + 4 C. 16xy2 + 5x2y + 4x – 4y3 + 4 D. 16xy2 + 5x2y + 4
@iambatman
will fan and medal
For example: \[10x^2+5x+3x^2-2x \implies 13x^2+3x\]
Do the same here, try it out, and see what you get.
Don't let the variables scare you :).
C?
Mhm lets write it out on LaTeX to make it clear.\[10xy^2+5x-4y^3+6-x+5x^2y+6xy^2-2\]
\[10\color{red}{xy^2}+5x-4y^3+6-x+5x^2y+6\color{red}{xy^2}-2\] lets do this first, what do we get when we add these terms?
136 xy?
I'm not sure what you did there, we're looking at the terms coloured in red.
\[10xy^2+6xy^2 =?\]
you just have to add coefficient of same variable and same exponent
\(10xy^2 + 5x - 4y^3 + 6 - x + 5x^2y + 6xy^2 - 2\) Combine \(10xy^2\) and \(6xy^2\): \(16xy^2 + 5x - 4y^3 + 6 - x + 5x^2y - 2\) Simplify \(5x - x\): \(16xy^2 + 4x - 4y^3 + 6 + 5x^2y - 2\) Simplify 6 - 2: \(16xy^2 + 4x - 4y^3 + 4 + 5x^2y\) Rearrange in order of highest exponents to lowest: \(16xy^2 + 5x^2y - 4y^3 + 4x + 4~\Large\color{lime} \checkmark\)
Your answer is correct :)
Or you can give answers, too many people answering questions, I'm out.
@iambatman I was just checking her answer.
|dw:1419257324809:dw| for example both number have y and both y have 2 both have x and both x have 1 exponent so they are same now just add 10 +6 = ??xy^2 lke iambatman said
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