Question

The function h(x) is quadratic and h(3) = h(–10) = 0. Which could represent h(x)?

h(x) = x2 – 13x – 30
h(x) = x2 – 7x – 30
h(x) = 2x2 + 26x – 60
h(x) = 2x2 + 14x – 60

Answer 1

@triciaal

Answer 2

you could plug in 3 and -10 into the h's given to see which would work...
or...
if you have h(a)=h(b)=0
then x=a and x=b are zeros
which means x-a and x-b are factors of h

Answer 3

@freckles C

Answer 4

can you tell me how you got that

Answer 5

Pluged In 3 @freckles

Answer 6

D imean

Answer 7

\[2(3)^2+26(3)-60 \\ 2(9)+78-60 \\ 18+78-60 \neq 0\]
ok D makes more since
I can also show you the other way I was talking about..
x=3 gives us h is 0
so x-3 is a factor
x=-10 gives us h is 0
so x+10 is a factor so we know
h(x)=c(x-3)(x+10)
where c is not 0
h(x)=c(x^2+7x-30)
and our case c is 2 here

Answer 8

sense* (not since :p)

Answer 9

So D is correct

Answer 10

h(3) is a zero so x-3 is a factor
h(-10) is a zero so x -(-10) is a factor
the factors are (x-3) and (x+10)
when you multiply these you get the function
h(x) = (x-3)(x + 10)
remember to watch the signs.

Answer 11

no the answer would be B