I dont get this....

Question

I dont get this....

undeadknight26 · Answer

Find the horizontal or oblique asymptote of f(x) =  (-3^2 + 7x + 1)/(x - 2).

undeadknight26 · Answer

y = 2
 y = -3
 y = 3x + 7
 y = -3x + 1

undeadknight26 · Answer

I graphed them all and none of them seem to match...

ganeshie8 · Answer

f(x) =  (-3x^2 + 7x + 1)/(x - 2)

like this right ?

undeadknight26 · Answer

Yup.

ganeshie8 · Answer

since the numerator is just one degree greater than the denominator, the function behaves like a straight line for large values of x

ganeshie8 · Answer

divide and take the quotient expression

ganeshie8 · Answer

oblique asymptote would be :
$$y = \text{quotient }$$

ganeshie8 · Answer

__________________
x-2 | -3x^2 + 7x + 1

undeadknight26 · Answer

i got (7x - 8)/x-2)...

ganeshie8 · Answer

you may do long division / synthetic division.. just get the quotient and you're done

ganeshie8 · Answer

-3x
       __________________
x-2 | -3x^2 + 7x + 1
         -3x^2 + 6x
       ------------
                        x + 1

ganeshie8 · Answer

` -3x + 1`
       __________________
x-2 | -3x^2 + 7x + 1
         -3x^2 + 6x
       ------------
                        x + 1
                        x - 2
                      ---------
                               3

ganeshie8 · Answer

the quotient is `-3x+1` so the oblique asymptote would be 
$$y = -3x+1$$

undeadknight26 · Answer

Thanks :D
I think i understand now sire!

ganeshie8 · Answer

yw:)

nnesha · Answer

omg this question close 
sorry i forgot that i was about to help you
actually i was on ohter post "debating post"
sorry 
and thanks ganeshie8