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Find the limit of the function algebraically. limit as x approaches nine of quantity x squared minus eighty one divided by quantity x minus nine.
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so the problem looks like \[\lim_{x \rightarrow 9} \frac{x^2 - 81}{x - 9}\] is that correct..?
\[\lim_{x \rightarrow 9} \frac{ x ^{2}-81 }{ x-9 }\]
use: \(\large\color{black}{ a^2-b^2=(a-b)(a+b) }\) for the top
so factor the numerator, its the difference of 2 squares.... then you'll see a common factor to remove. and finally substitute x = 9 into whats left to find the limit
yes, well is the answer 18? I did (x+9)(x-9)/(x-9), simplified it to (x+9) and substituted 9 for x and added and got 18...
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yes.
that is right:)
Ok thanks so much:)) you rock:))
well done
you welcome!
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