Question

PLZ HELP WILL FAN AND MEDAL

Answer 1

yes what is your question?

Answer 2

Assume you are performing a cross between a plant that is heterozygous for the dominant traits red flowers and wrinkled seeds, with a plant that is homozygous for the recessive traits white flowers and smooth seeds. Assume the alleles are R for red flowers, r for white flowers, W for wrinkled seeds, and w for smooth seeds. The offspring of this cross show the following phenotypes:

43 red flowers and wrinkled seeds

7 red flowers and smooth seeds

9 white flowers and wrinkled seeds

41 white flowers and smooth seeds

What are the traits of the recombinant offspring in terms of flower color and seed shape? Explain how you know that these offspring are recombinant. What alleles would you expect to see in the individual chromosomes of each parent before and after crossing-over takes place? What is the recombination frequency? What is the distance between the genes in map units?

Answer 3

Hint: To calculate the recombination frequency, or the percentage of recombinants in the population, use this equation: total number of recombinant offspring (divided by) total number offspring = recombinant frequency. Then use that number to calculate the distance in map units between the genes. Use this equation: distance = recombination frequency x 100.

Answer 4

omg ur gonna have to give me a minute to think this one out

Answer 5

okay

Answer 6

okay so first thing. identify all that you need within the equation once you are done tell me what you got

Answer 7

Assume you are performing a cross between a plant that is heterozygous for the dominant traits red flowers and wrinkled seeds, with a plant that is homozygous for the recessive traits white flowers and smooth seeds.

43 red flowers and wrinkled seeds
7 red flowers and smooth seeds
9 white flowers and wrinkled seeds
41 white flowers and smooth seeds

Answer 8

okay lets do the heterozygous first
set up the equation that you need

Answer 9

idk how thats the problem

Answer 10

okay hold on let me get someone else here

Answer 11

@Ashchu117 @DarkMoonZ

Answer 12

This is fun question, and can be figured out by drawing a Punnett rectangle. The heterozygous parent produces the gametes RW, Rw, rW, and rw. The homozygous parent produces only the gamete rw. So the resultant Punnett rectangle is a 1x4, and we would expect to produce 4 genotypes: RrWw, Rrww, rrWw, and rrww in equal numbers. Note that these are also 4 different phenotypes.

But we don't. We have too many Red/Wrinkled and White/Smooth. Therefore, the red and wrinkled alleles must be on the same chromosome (they are linked). Same is true of the white and smooth alleles.

The recombinant offspring are the other two phenotypes. There are 16 recombinant offspring out of 100 total, so the percentage of recombinants is 16/100 or 16%.

By convention, each percent cross-over frequency equals 1 map unit, so the two alleles are 16 map units apart

Answer 13

does that help?

Answer 14

hmm

Answer 15

I would give you a medal but that wasnt in your own words?

Answer 16

yah, i don't mind as long as it helped

Answer 17

Dammit Im late to the party again