Find the slope and the y-intercept of the equation 4x + 5y = -9. MEDAL WILL BE GIVEN
okay so how would you normally go about finding the slope of an equation?
y=mx+b?
Yes, that's right. The first step is to solve for y in terms of x. So 4x+5y=-9 5y=-4x-9 y=-4/5x-9/5
now you have y=mx+b; y=-4/5x-9/5
what's your m?
-4/5?
Yep you got it
only thing left in the problem is to find the y intercept. Do you know how to do that?
A line parallel to the A.Y int. Or B.X-Int has no defined slope, and a line parallel to the A.Y int. Or B.X-Int has a slope of zero? do you know that
don't you still need to find the y intercept?
it was -9/5
oh good. okay you got it.
well, when does a line have a slope of zero?
undefined?
let me rephrase the question. what is the slope of a horizontal line?
0?
you are right but why?
I don't know parallel? No slope?
a horizontal line has the same why everywhere along the line. the only thing that changes is the x.
y*
so by the slope formula: y2-y1/x2-x1=slope=0 because y2-y1=0
y2-y1=0 because the y never changes on a horizontal line. so consider a vertical line where the y is always changing but the x is always the same
by the slope formula: y2-y1/x2-x1=slope=undefined. this is because x2-x1=0 and therefore; y2-y1/0=undefined since you can never divide by a 0
does that make sense
not really , so does a line parallel to the y axis has no defined slope?
yes
and a line parallel to the x-axis has a slope of zero?
yes
If a line with a slope of -2 crosses the y-axis at (0, 3), what is the equation of the line? would it be y+2x=3?
yes
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