Write your problem (numbers) and scroll down and it gives you detailed information
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OpenStudy (lizz123):
@feathert03s
OpenStudy (anonymous):
@lizz123 i want the x to be up with the 2 how do i do that
OpenStudy (lizz123):
you write the 2 with the x
it does numbers and letters
OpenStudy (anonymous):
This is what its doing
i need it to have 2x as an exponent
OpenStudy (anonymous):
@lizz123
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OpenStudy (lizz123):
oh idk sorry
OpenStudy (mathmate):
Hint: Express both sides as a power of 8.
\(\Large 8^{2x}=4096=8^4\)
Solve for x.
OpenStudy (anonymous):
what? that doesn't make sense
OpenStudy (anonymous):
where did you get ^4 from @mathmate
OpenStudy (anonymous):
@calculusfunctions
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OpenStudy (anonymous):
@SolomonZelman
OpenStudy (mathmate):
If you keep dividing 4096 by eight, and count how many times you divide before you get a one.
I.e. 4096/8/8.../8 will tell you 8*8*..*8 = 8 raised to how many times will give 4096.
OpenStudy (mathmate):
The other way to do it is to factorize 4096 into powers of two, and work from there.
OpenStudy (anonymous):
ohk so x=?
OpenStudy (calculusfunctions):
Try to equate the bases (which you can in your question). In other words, first write 4096 as a power of 8.
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OpenStudy (anonymous):
we have 8^4
OpenStudy (mathmate):
So that's the right hand side of 8^4.
Can you now solve for x?
OpenStudy (anonymous):
no because there are two =
OpenStudy (calculusfunctions):
Since the 4th power of 8 is 4096,\[8^{2x}=4096\]is equivalent to\[8^{2x}=8^{4}\]Now if the bases are equal, then the exponents are equal. Thus\[2x =4\]
OpenStudy (calculusfunctions):
Understand @feathert03s ?
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OpenStudy (mathmate):
The middle is just an intermediate step.
The left hand side still equals the right hand side, right?